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MHT CET 2026 (11 Apr, Shift 2) · Resolving Power

Resolving Power question from MHT CET 2026 (11 Apr, Shift 2)

Q7MHT CET 2026 · 11 APR · SHIFT 2Medium

Resolving Power

Converging lens of telescope 55 cm in diameter has focal length 2525 cm. In the focal plane of the lens the distance between the centres of the Fraunhofer diffraction pattern is (wavelength of light used = 50005000 Å, Rayleigh's criterion is satisfied)

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Answer: (c)

  1. Angular separation for just-resolved images θ=1.22λD\theta = \dfrac{1.22\lambda}{D}; in the focal plane x=fθx = f\theta.
  2. x=1.22λfD=1.22×5000×255x = \dfrac{1.22\lambda f}{D} = \dfrac{1.22 \times 5000 \times 25}{5} Å
  3. x=30500x = 30500 Å
  4. So the answer is (c) 3050030500 Å.
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