Copper has face centered cubic (fcc) lattice with interatomic spacing equal to 2.54. The value of lattice constant for this lattice is (a) 2.54 (b) 3.59 (c) 1.27 (d) 5.08

Answer: (b). In FCC, nearest-neighbour (interatomic) spacing is half the face diagonal: d = a/√(2). a = √(2) d = 1.414 × 2.54 a ≈ 3.59 So the answer is (b) 3.59.

Copper has face centered cubic (fcc) lattice with interatomic spacing… | NEET 2005 (AIPMT)

Q7NEET 2005 · AIPMTMedium

Other / Mixed

${}$ Copper has face centered cubic (fcc) lattice with interatomic spacing equal to 2.54 $\text{\AA}$ . The value of lattice constant for this lattice is

Show answer and solution

Answer: (b)

In FCC, nearest-neighbour (interatomic) spacing is half the face diagonal: $d = \frac{a}{\sqrt{2}}$ .
$a = \sqrt{2}\,d = 1.414 \times 2.54$
$a \approx 3.59\ \text{\AA}$
So the answer is (b) 3.59 $\text{\AA}$ .

Report a mistake

Other / Mixed question from NEET 2005 (AIPMT)

More questions on Other / Mixed