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JEE Main 2025 (4 Apr, Shift 1) · Electric Current, Drift Velocity & Current Density

Electric Current, Drift Velocity & Current Density question from JEE Main 2025 (4 Apr, Shift 1)

Q3JEE Main 2025 · 4 APR · SHIFT 1Easy

Electric Current, Drift Velocity & Current Density

Current passing through a wire as function of time is given as I(t)=0.02t+0.01 AI(t) = 0.02t + 0.01\text{ A}. The charge that will flow through the wire from t=1 st = 1\text{ s} to t=2 st = 2\text{ s} is

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Answer: (d)

  1. Charge q=∫I dt=∫12(0.02t+0.01) dtq = \int I\,dt = \int_1^2 (0.02t + 0.01)\,dt
  2. q=[0.01t2+0.01t]12=(0.04+0.02)−(0.01+0.01)q = \left[0.01t^{2} + 0.01t\right]_1^2 = (0.04 + 0.02) - (0.01 + 0.01)
  3. q=0.04 Cq = 0.04\text{ C}
  4. So the answer is (d) 0.04 C.
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