Physics Circle home Student Login

Home›Chapters›Dual Nature of Radiation and Matter PYQs›Matter Waves: de Broglie Wavelength›Question 41

NEET 2025 · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from NEET 2025

Q41NEET 2025Medium

Matter Waves: de Broglie Wavelength

De-Broglie wavelength of an electron orbiting in the n=2n = 2 state of hydrogen atom is close to (Given Bohr radius =0.052 nm= 0.052\text{ nm})

Show answer and solution

Answer: (d)

  1. 2πrn=nλ⇒λ=2πrnn2\pi r_n = n\lambda \Rightarrow \lambda = \dfrac{2\pi r_n}{n}
  2. r2=4a0=4×0.052=0.208r_2 = 4a_0 = 4\times0.052 = 0.208 nm
  3. λ=2π×0.2082≈0.65\lambda = \dfrac{2\pi\times0.208}{2} \approx 0.65 nm
  4. So the answer is (d) 0.67 nm (closest).
Report a mistake

More questions on Matter Waves: de Broglie Wavelength