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MHT CET 2026 (15 Apr, Shift 1) · Pure R, L and C Circuits

Pure R, L and C Circuits question from MHT CET 2026 (15 Apr, Shift 1)

Q14MHT CET 2026 · 15 APR · SHIFT 1Easy

Pure R, L and C Circuits

Determine the frequency for which a 10 μ10\ \muF capacitor has a reactance of 2×10−3 Ω2 \times 10^{-3}\ \Omega.

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Answer: (a)

  1. XC=12πfC⇒f=12πCXCX_C = \frac{1}{2\pi f C} \Rightarrow f = \frac{1}{2\pi C X_C}
  2. f=12π×10×10−6×2×10−3=14π×10−8=25×106πf = \frac{1}{2\pi \times 10 \times 10^{-6} \times 2 \times 10^{-3}} = \frac{1}{4\pi \times 10^{-8}} = \frac{25 \times 10^{6}}{\pi} Hz
  3. So the answer is (a) 25π\frac{25}{\pi} MHz.
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