Physics Circle home Student Login

Home›Chapters›Wave Optics PYQs›Resolving Power›Question 17

JEE Main 2019 (9 Apr, Shift 2) · Resolving Power

Resolving Power question from JEE Main 2019 (9 Apr, Shift 2)

Q17JEE Main 2019 · 9 APR · SHIFT 2Easy

Resolving Power

Diameter of the objective lens of a telescope is 250 cm. For light of wavelength 600nm. coming from a distant object, the limit of resolution of the telescope is close to :-

Show answer and solution

Answer: (a)

  1. θ=1.22λD\theta = \dfrac{1.22\lambda}{D} with D=2.5D = 2.5 m, λ=600×10−9\lambda = 600\times10^{-9} m.
  2. θ=1.22×600×10−92.5=2.93×10−7\theta = \dfrac{1.22\times600\times10^{-9}}{2.5} = 2.93\times10^{-7} rad
  3. So the answer is (a) 3.0×10−73.0\times10^{-7} rad (closest).
Report a mistake

More questions on Resolving Power