Physics Circle home Student Login

Home›Chapters›Units, Dimensions and Measurement PYQs›Units & Dimensions›Question 117

NEET 1989 (AIPMT) · Units & Dimensions

Units & Dimensions question from NEET 1989 (AIPMT)

Q117NEET 1989 · AIPMTEasy

Units & Dimensions

Dimensional formula of self inductance is

Show answer and solution

Answer: (c)

  1. U=12LI2⇒L=2UI2U = \frac{1}{2}LI^2 \Rightarrow L = \frac{2U}{I^2}
  2. [L]=[ML2T−2][A2]=[ML2T−2A−2][L] = \frac{[\mathrm{ML^2T^{-2}}]}{[\mathrm{A^2}]} = [\mathrm{ML^2T^{-2}A^{-2}}]
  3. So the answer is (c).
Report a mistake

More questions on Units & Dimensions