Displacement of a wave is expressed as x(t) = 5cos (628t + π/2)m. The wavelength of the wave when its velocity is 300 m/s is: (π = 3.14) (a) 0.33 m (b) 0.5 m (c) 3 m (d) 5 m

Answer: (c). ω = 628 rad/s, so f = (628)/(2 × 3.14) = 100 Hz. λ = v/f = (300)/(100) = 3 m So the answer is (c) 3 m.

Displacement of a wave is expressed as x(t) = 5cos (628t + π/2)m. The… | JEE Main 2025 (4 Apr, Shift 2)

Q26JEE Main 2025 · 4 APR · SHIFT 2Easy

Progressive Wave Equation

Displacement of a wave is expressed as $x(t) = 5\cos\left(628t + \frac{\pi}{2}\right)\text{m}$ . The wavelength of the wave when its velocity is $300\text{ m/s}$ is:

$(\pi = 3.14)$

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Answer: (c)

$\omega = 628\text{ rad/s}$ , so $f = \dfrac{628}{2 \times 3.14} = 100\text{ Hz}$ .
$\lambda = \dfrac{v}{f} = \dfrac{300}{100} = 3\text{ m}$
So the answer is (c) $3\text{ m}$ .

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