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NEET 1995 (AIPMT) · Other / Mixed

Other / Mixed question from NEET 1995 (AIPMT)

Q12NEET 1995 · AIPMTMedium

Other / Mixed

Distance between body centred atom and a corner atom in sodium (a=4.225a = 4.225 Å) is

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Answer: (c)

  1. Body centre to corner is half the body diagonal: d=32ad = \frac{\sqrt{3}}{2}a.
  2. d=0.866×4.225d = 0.866 \times 4.225
  3. d≈3.66d \approx 3.66 Å
  4. So the answer is (c) 3.66 Å.
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