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MHT CET 2024 (16 May, Shift 2) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2024 (16 May, Shift 2)

Q132MHT CET 2024 · 16 MAY · SHIFT 2Difficult

Thermodynamic Processes

During an experiment, an ideal gas is found to obey an additional law $VP^{2} =$ constant. The gas is initially at temperature ' T ' and volume ' V '. What will be the temperature of the gas when it expands to a volume 2 V?

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Answer: (c)

$VP^2 =$ constant $\Rightarrow P \propto V^{-1/2}$ .
$T \propto PV \propto V^{1/2}$
$V \to 2V$ : $T' = \sqrt{2}\,T$ , so the answer is (c).

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