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NEET 2011 (AIPMT, Prelims) · Thermodynamic Processes

Thermodynamic Processes question from NEET 2011 (AIPMT, Prelims)

Q239NEET 2011 · AIPMT · PRELIMSEasy

Thermodynamic Processes

During an isothermal expansion, a confined ideal gas does −- 150 J of work against its surroundings. This implies that

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Answer: (d)

  1. Isothermal: ΔU=0\Delta U = 0, so Q=WQ = W.
  2. W=−150W = -150 J ⇒Q=−150\Rightarrow Q = -150 J.
  3. Negative QQ means 150 J of heat is removed from the gas.
  4. By this working the answer is (a); the official key gives (d).
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