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JEE Main 2024 (30 Jan, Shift 1) · Elastic Behaviour, Stress & Strain

Elastic Behaviour, Stress & Strain question from JEE Main 2024 (30 Jan, Shift 1)

Q8JEE Main 2024 · 30 JAN · SHIFT 1Medium

Elastic Behaviour, Stress & Strain

Each of three blocks P,QP, Q andRR shown in figure has a mass of 3 kg3\text{ kg}. Each of the wires AA and BB has cross-sectional area 0.005 cm20.005\text{ cm}^2 and Young's modulus 2×1011 N m−22 \times 10^{11}\text{ N m}^{-2}. Neglecting friction, the longitudinal strain on wire BB is ________ ×10−4\times 10^{-4}. (Take g=10 m/s2g = 10\text{ m/s}^2)

Figure

Numerical answer type. Work it out, then open the answer.

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Answer: 2

PQT_BP + Q (6 kg)T_B = (6 kg) a = 6 x 10/3 = 20 Na = 30 N / 9 kg = 10/3 m/s²
  1. Whole system: a=mRgmP+mQ+mR=309=103 m/s2a = \frac{m_R g}{m_P + m_Q + m_R} = \frac{30}{9} = \frac{10}{3}\ \text{m/s}^2
  2. Wire BB pulls both PP and QQ: TB=(mP+mQ)a=6×103=20 NT_B = (m_P + m_Q)a = 6 \times \frac{10}{3} = 20\ \text{N}
  3. A=0.005 cm2=5×10−7 m2A = 0.005\ \text{cm}^2 = 5 \times 10^{-7}\ \text{m}^2
  4. Strain =TBAY=205×10−7×2×1011=2×10−4= \frac{T_B}{AY} = \frac{20}{5 \times 10^{-7} \times 2 \times 10^{11}} = 2 \times 10^{-4}
  5. Answer: 22
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