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JEE Main 2025 (28 Jan, Shift 2) · Escape Velocity

Escape Velocity question from JEE Main 2025 (28 Jan, Shift 2)

Q12JEE Main 2025 · 28 JAN · SHIFT 2Easy

Escape Velocity

Earth has mass 8 times and radius 2 times that of a planet. If the escape velocity from the earth is 11.2 km/s, the escape velocity in km/s from the planet will be:

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Answer: (c)

$v_e \propto \sqrt{\frac{M}{R}}$ ; planet has $\frac{M}{8}$ and $\frac{R}{2}$
$v_p = 11.2\sqrt{\frac{1/8}{1/2}} = 11.2 \times \frac{1}{2} = 5.6$ km/s
So the answer is (c) 5.6.

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