Eight identical drops of water falling through air with uniform velocity of 10 cm/s combine to form a single drop of big size, then terminal velocity of the big drop will be (a) 80 cm/s (b) 10 cm/s (c) 30 cm/s (d) 40 cm/s

Answer: (d). v ∝ r² and R = n1/3r, so v' = n2/3v. n = 8 ⇒ n2/3 = 4 v' = 4 × 10 = 40 cm/s So the answer is (d) 40 cm/s.

Eight identical drops of water falling through air with uniform… | MHT CET 2019 (3 May, Shift 1)

Q48MHT CET 2019 · 3 MAY · SHIFT 1Easy

Terminal Velocity

Eight identical drops of water falling through air with uniform velocity of $10\text{ cm/s}$ combine to form a single drop of big size, then terminal velocity of the big drop will be

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Answer: (d)

$v \propto r^2$ and $R = n^{1/3}r$ , so $v' = n^{2/3}v$ .
$n = 8 \Rightarrow n^{2/3} = 4$
$v' = 4 \times 10 = 40$ cm/s
So the answer is (d) 40 cm/s.

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