Physics Circle home Student Login

Home›Chapters›Surface Tension PYQs›Splitting & Merging of Drops›Question 33

MHT CET 2023 (12 May, Shift 2) · Splitting & Merging of Drops

Splitting & Merging of Drops question from MHT CET 2023 (12 May, Shift 2)

Q33MHT CET 2023 · 12 MAY · SHIFT 2Easy

Splitting & Merging of Drops

Eight small drops of mercury each of radius 'rr', coalesce to form a large single drop. The ratio of total surface energy before and after the change is

Show answer and solution

Answer: (a)

  1. Volume conserved: R=81/3r=2rR = 8^{1/3}r = 2r.
  2. Ebefore=8×4πr2T=32πr2TE_{before} = 8 \times 4\pi r^2 T = 32\pi r^2 T, Eafter=4π(2r)2T=16πr2TE_{after} = 4\pi(2r)^2 T = 16\pi r^2 T
  3. Ebefore:Eafter=2:1E_{before} : E_{after} = 2 : 1
  4. So the answer is (a) 2:12:1.
Report a mistake

More questions on Splitting & Merging of Drops