Electric field at centre O of semicircle of radius a having linear charge density λ given as (a) (2λ)/(ε₀ a) (b) (λπ)/(ε₀ a) (c) (λ)/(2πε₀ a) (d) (λ)/(πε₀ a)

Answer: (c). Field at the centre of a uniformly charged semicircular arc: E = (2kλ)/(a) = (2λ)/(4πε₀ a). E = (λ)/(2πε₀ a) So the answer is (c) (λ)/(2πε₀ a).

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Electric Field & Field Lines

Electric field at centre O of semicircle of radius $a$ having linear charge density $\lambda$ given as

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Answer: (c)

Field at the centre of a uniformly charged semicircular arc: $E = \dfrac{2k\lambda}{a} = \dfrac{2\lambda}{4\pi\varepsilon_0 a}$ .
$E = \dfrac{\lambda}{2\pi\varepsilon_0 a}$
So the answer is (c) $\dfrac{\lambda}{2\pi\varepsilon_0 a}$ .

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