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JEE Main 2023 (30 Jan, Shift 1) · Electric Field & Field Lines

Electric Field & Field Lines question from JEE Main 2023 (30 Jan, Shift 1)

Q19JEE Main 2023 · 30 JAN · SHIFT 1Easy

Electric Field & Field Lines

Electric field in a certain region is given by E⃗=(Ax2i^+By3j^)\vec{E} = \left(\frac{A}{x^2}\hat{i} + \frac{B}{y^3}\hat{j}\right). The SI\text{SI} unit of AA and BB are:

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Answer: (d)

  1. Each term must have the unit of EE, i.e. N C−1\text{N C}^{-1}.
  2. Ax2=N C−1⇒A=N m2C−1\dfrac{A}{x^2} = \text{N C}^{-1} \Rightarrow A = \text{N m}^2\text{C}^{-1}
  3. By3=N C−1⇒B=N m3C−1\dfrac{B}{y^3} = \text{N C}^{-1} \Rightarrow B = \text{N m}^3\text{C}^{-1}
  4. So the answer is (d).
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