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JEE Main 2026 (22 Jan, Shift 1) · Electric Potential & Equipotentials

Electric Potential & Equipotentials question from JEE Main 2026 (22 Jan, Shift 1)

Q20JEE Main 2026 · 22 JAN · SHIFT 1Medium

Electric Potential & Equipotentials

Electric field in a region is given by E⃗=Axi^+Byj^\vec{E} = Ax\hat{i} + By\hat{j}, where A=10 V/m2A = 10\text{ V/m}^2 and B=5 V/m2B = 5\text{ V/m}^2. If the electric potential at a point (10,20)(10, 20) is 500 V, then the electric potential at origin is ______ V.

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Answer: (c)

  1. VO−VP=−∫POE⃗⋅dr⃗=[Ax22+By22]OPV_O - V_P = -\int_P^O \vec{E}\cdot d\vec{r} = \left[\frac{Ax^2}{2} + \frac{By^2}{2}\right]_{O}^{P}
  2. =10(10)22+5(20)22=500+1000=1500 V= \frac{10(10)^2}{2} + \frac{5(20)^2}{2} = 500 + 1000 = 1500\,\text{V}
  3. VO=500+1500=2000 VV_O = 500 + 1500 = 2000\,\text{V}
  4. So the answer is (c) 2000.
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