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MHT CET 2023 (10 May, Shift 1) · Moving Charge in a Magnetic Field

Moving Charge in a Magnetic Field question from MHT CET 2023 (10 May, Shift 1)

Q46MHT CET 2023 · 10 MAY · SHIFT 1Medium

Moving Charge in a Magnetic Field

Electron of mass ' $m$ ' and charge ' $q$ ' is travelling with speed ' $v$ ' along a circular path of radius ' $R$ ', at right angles to a uniform magnetic field of intensity ' $B$ '. If the speed of the electron is halved and the magnetic field is doubled, the resulting path would have radius

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Answer: (d)

$R = \dfrac{mv}{qB} \Rightarrow R \propto \dfrac{v}{B}$
$R' = \dfrac{m(v/2)}{q(2B)} = \dfrac{R}{4}$
So the answer is (d) $\frac{R}{4}$ .

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