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MHT CET 2024 (10 May, Shift 1) · Moving Charge in a Magnetic Field

Moving Charge in a Magnetic Field question from MHT CET 2024 (10 May, Shift 1)

Q34MHT CET 2024 · 10 MAY · SHIFT 1Medium

Moving Charge in a Magnetic Field

Electron of mass ' mm ' and charge ' qq ' is travelling with speed ' vv ' along a circular path of radius ' RR ' at right angles to a uniform magnetic field of intensity ' B '. If the speed of the electron is halved and the magnetic field is doubled, the resulting path would have radius

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Answer: (b)

  1. R=mvqB⇒R∝vBR = \dfrac{mv}{qB} \Rightarrow R \propto \dfrac{v}{B}
  2. R′=m(v/2)q(2B)=R4R' = \dfrac{m(v/2)}{q(2B)} = \dfrac{R}{4}
  3. So the answer is (b) R4\frac{R}{4}.
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