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MHT CET 2024 (15 May, Shift 1) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from MHT CET 2024 (15 May, Shift 1)

Q50MHT CET 2024 · 15 MAY · SHIFT 1Easy

Matter Waves: de Broglie Wavelength

Electrons are accelerated through a potential difference of 16 kV. If the potential difference is increased to 64 kV, then de-Broglie wavelength associated with electron will

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Answer: (b)

$\lambda \propto \dfrac{1}{\sqrt{V}}$ .
$\dfrac{\lambda'}{\lambda} = \sqrt{\dfrac{16}{64}} = \dfrac{1}{2}$ .
So the answer is (b) becomes half.

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