Energy released in the fission of a single ²³⁵₉₂U nucleus is 200 MeV. The fission rate of ²³⁵₉₂U filled reactor operating at a power level of 5 W is (a) 1.56 × 10⁻¹⁰ s⁻¹ (b) 1.56 × 10¹¹ s⁻¹ (c) 1.56 × 10⁻¹⁶ s⁻¹ (d) 1.56 × 10⁻¹⁷ s⁻¹

Answer: (b). Energy per fission = 200×1.6×10⁻¹³ = 3.2×10⁻¹¹ J. Fission rate = P/E = 53.2×10⁻¹¹ = 1.56×10¹¹ s⁻¹. So the answer is (b).

Energy released in the fission of a single ²³⁵₉₂U nucleus is 200 MeV… | NEET 1993 (AIPMT)

Q43NEET 1993 · AIPMTMedium

Nuclear Fission & Fusion

Energy released in the fission of a single ${}^{235}_{92}\text{U}$ nucleus is 200 MeV. The fission rate of ${}^{235}_{92}\text{U}$ filled reactor operating at a power level of 5 W is

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Answer: (b)

Energy per fission $= 200\times1.6\times10^{-13} = 3.2\times10^{-11}\text{ J}$ .
Fission rate $= \dfrac{P}{E} = \dfrac{5}{3.2\times10^{-11}} = 1.56\times10^{11}\text{ s}^{-1}$ .
So the answer is (b).

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