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NEET 1988 (AIPMT) · Progressive Wave Equation

Progressive Wave Equation question from NEET 1988 (AIPMT)

Q109NEET 1988 · AIPMTEasy

Progressive Wave Equation

Equation of progressive wave is given by y=4sin⁡[π(t5−x9)+π6]y = 4\sin\left[\pi\left(\frac{t}{5} - \frac{x}{9}\right) + \frac{\pi}{6}\right] where y,xy, x are in cm and tt is in seconds. Then which of the following is correct?

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Answer: (b)

  1. y=4sin⁡(π5t−π9x+π6)y = 4\sin\left(\dfrac{\pi}{5}t - \dfrac{\pi}{9}x + \dfrac{\pi}{6}\right): A=4 cmA = 4\text{ cm}, ω=π5\omega = \dfrac{\pi}{5}, k=π9k = \dfrac{\pi}{9}.
  2. λ=2ππ/9=18 cm\lambda = \dfrac{2\pi}{\pi/9} = 18\text{ cm}; v=95=1.8 cm/sv = \dfrac{9}{5} = 1.8\text{ cm/s}; f=0.1 Hzf = 0.1\text{ Hz}
  3. So the answer is (b) λ=18 cm\lambda = 18\text{ cm}.
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