Equation of simple harmonic progressive wave is given by y = 1/√(a)sin ω t ± 1/√(b)cos ω t then the resultant amplitude of the wave is (cos 90° = 0) (a) (a ± b)/(ab) (b) (√(a) ± √(b))/(ab) (c) (√(a) ± √(b))/(√(ab)) (d) √((a + b)/(ab))

Answer: (d). sin ω t and cos ω t differ in phase by 90°, so AR = √(A₁² + A₂²) AR = √(1/a + 1/b) = √((a + b)/(ab)) So the answer is (d) √(a+b/ab).

Equation of simple harmonic progressive wave is given by y =… | MHT CET 2023 (9 May, Shift 1)

Q10MHT CET 2023 · 9 MAY · SHIFT 1Easy

Reflection, Superposition & Interference

Equation of simple harmonic progressive wave is given by $y = \frac{1}{\sqrt{a}}\sin\omega t \pm \frac{1}{\sqrt{b}}\cos\omega t$ then the resultant amplitude of the wave is $(\cos 90^\circ = 0)$

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Answer: (d)

$\sin\omega t$ and $\cos\omega t$ differ in phase by $90^\circ$ , so $A_R = \sqrt{A_1^2 + A_2^2}$
$A_R = \sqrt{\frac{1}{a} + \frac{1}{b}} = \sqrt{\frac{a + b}{ab}}$
So the answer is (d) $\sqrt{\frac{a+b}{ab}}$ .

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Reflection, Superposition & Interference question from MHT CET 2023 (9 May, Shift 1)

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