Student Login

Home›Chapters›Gravitation PYQs›Escape Velocity›Question 20

JEE Main 2024 (30 Jan, Shift 2) · Escape Velocity

Escape Velocity question from JEE Main 2024 (30 Jan, Shift 2)

Q20JEE Main 2024 · 30 JAN · SHIFT 2Easy

Escape Velocity

Escape velocity of a body from earth is $11.2\text{ km/s}$ . If the radius of a planet be one-third the radius of earth and mass be one-sixth that of earth, the escape velocity from the planet is:

Show answer and solution

Answer: (a)

$v_e \propto \sqrt{\frac{M}{R}}$
$v_p = 11.2\sqrt{\frac{1/6}{1/3}} = \frac{11.2}{\sqrt{2}} \approx 7.9$ km/s
So the answer is (a) 7.9 km/s.

Report a mistake

More questions on Escape Velocity

The radius and mean density of the planet are four times as that of the earth. The ratio…MHT CET 2024 (10 May, Shift 1)
A body is projected in vertically upward direction from the surface of the earth of…MHT CET 2024 (11 May, Shift 2)
A body starts from rest from a distance R₀ from the centre of the earth. The velocity…MHT CET 2024 (10 May, Shift 2)
Earth has mass ' M₁ ' radius ' R₁ ' and for moon mass ' M₂ ' and radius ' R₂ '. Distance…MHT CET 2024 (3 May, Shift 1)
Given below are two statements: Statement I: For a planet, if the ratio of mass of the…JEE Main 2023 (13 Apr, Shift 2)
A planet having mass 9Me and radius 4Re, where Me and Re are mass and radius of earth…JEE Main 2023 (13 Apr, Shift 1)
The ratio of escape velocity of a planet to the escape velocity of earth will be:- Given…JEE Main 2023 (12 Apr, Shift 1)
Given below are two statements: one is labelled as Assertion A and the other is labelled…JEE Main 2023 (6 Apr, Shift 1)