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MHT CET 2021 (21 Sep, Shift 1) · Electric Charge & Coulomb's Law

Electric Charge & Coulomb's Law question from MHT CET 2021 (21 Sep, Shift 1)

Q52MHT CET 2021 · 21 SEP · SHIFT 1Easy

Electric Charge & Coulomb's Law

'FF' is the force between the two identical charged particles placed at a distance 'YY' from each other. If the distance between the charges is reduced to half the previous distance then force between them becomes

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Answer: (b)

  1. F∝1r2F \propto \dfrac{1}{r^2}.
  2. r→Y2⇒F′=F(1/2)2=4Fr \to \dfrac{Y}{2} \Rightarrow F' = \dfrac{F}{(1/2)^2} = 4F
  3. So the answer is (b) 4F4F.
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