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MHT CET 2026 (18 Apr, Shift 1) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from MHT CET 2026 (18 Apr, Shift 1)

Q16MHT CET 2026 · 18 APR · SHIFT 1Medium

Organ Pipes & Resonance Tube

Fifth overtone of an open pipe of length $L_0$ is in unison with the fifth overtone of the pipe closed at one end of length $L_c$ .

The ratio $L_0$ to $L_c$ is

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Answer: (d)

Open pipe, fifth overtone (6th harmonic): $\frac{6v}{2L_0} = \frac{3v}{L_0}$ .
Closed pipe, fifth overtone (11th harmonic): $\frac{11v}{4L_c}$ .
$\frac{3}{L_0} = \frac{11}{4L_c} \Rightarrow \frac{L_0}{L_c} = \frac{12}{11}$
So the answer is (d) $12 : 11$ .

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