Figure below shows a liquid being pushed out of the tube by a piston having area of cross section 2.0 cm². The area of cross section at the outlet is 10 mm². If the piston is pushed at a speed of 4 cm s⁻¹, the speed of outgoing fluid is __________ cms⁻¹ Numerical answer type. Work it out, then open the answer.

Answer: 80. Continuity: A₁v₁ = A₂v₂, with A₁ = 2.0 cm² = 200 mm² v₂ = 200/10× 4 = 80 cm/s So the answer is 80 cm s ⁻¹.

Figure below shows a liquid being pushed out of the tube by a piston… | JEE Main 2023 (10 Apr, Shift 2)

Q19JEE Main 2023 · 10 APR · SHIFT 2Difficult

Bernoulli's Equation

Figure below shows a liquid being pushed out of the tube by a piston having area of cross section $2.0\text{ cm}^2$ . The area of cross section at the outlet is $10\text{ mm}^2$ . If the piston is pushed at a speed of $4\text{ cm s}^{-1}$ , the speed of outgoing fluid is __________ $\text{cms}^{-1}$

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 80

Continuity: $A_1v_1 = A_2v_2$ , with $A_1 = 2.0\text{ cm}^2 = 200\text{ mm}^2$
$v_2 = \frac{200}{10}\times 4 = 80\text{ cm/s}$
So the answer is $80$ cm s $^{-1}$ .

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Bernoulli's Equation question from JEE Main 2023 (10 Apr, Shift 2)

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