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NEET 2015 (AIPMT, Cancelled Paper) · P-V Diagrams & Cyclic Processes

P-V Diagrams & Cyclic Processes question from NEET 2015 (AIPMT, Cancelled Paper)

Q71NEET 2015 · AIPMT · CANCELLED PAPERMedium

P-V Diagrams & Cyclic Processes

Figure below shows two paths that may be taken by a gas to go from a state A to a state C.

Figure

In process AB, 400 J of heat is added to the system and in process BC, 100 J of heat is added to the system. The heat absorbed by the system in the process AC will be

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Answer: (a)

  1. From the figure: VA=2×10−3V_A = 2 \times 10^{-3}, VC=4×10−3 m3V_C = 4 \times 10^{-3}\ \text{m}^3; PA=2×104P_A = 2 \times 10^4, PB=PC=6×104 PaP_B = P_C = 6 \times 10^4\ \text{Pa}.
  2. Path ABC: Q=400+100=500 JQ = 400 + 100 = 500\ \text{J}, W=WBC=6×104×2×10−3=120 JW = W_{BC} = 6 \times 10^4 \times 2 \times 10^{-3} = 120\ \text{J}, so ΔU=380 J\Delta U = 380\ \text{J}.
  3. Path AC (trapezium): W=12(2+6)×104×2×10−3=80 JW = \frac{1}{2}(2 + 6) \times 10^4 \times 2 \times 10^{-3} = 80\ \text{J}
  4. QAC=ΔU+W=380+80=460 JQ_{AC} = \Delta U + W = 380 + 80 = 460\ \text{J}
  5. So the answer is (a) 460 J.
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