Physics Circle home Student Login

Home›Chapters›Centre of Mass PYQs›Composite & Cut-Out Bodies›Question 1

MHT CET 2026 (13 May, Shift 2) · Composite & Cut-Out Bodies

Composite & Cut-Out Bodies question from MHT CET 2026 (13 May, Shift 2)

Q1MHT CET 2026 · 13 MAY · SHIFT 2Medium

Composite & Cut-Out Bodies

Figure shows a composite system of two uniform rods of length as shown. The co-ordinates of the centre of mass of the system of rods are

Figure

Show answer and solution

Answer: (c)

  1. Uniform rods: mass ∝\propto length. Vertical rod 2m2m with CM at (0,L)(0, L); horizontal rod mm with CM at (L2,0)\left(\frac{L}{2}, 0\right).
  2. xcm=m⋅L23m=L6x_{cm} = \frac{m \cdot \frac{L}{2}}{3m} = \frac{L}{6}
  3. ycm=2m⋅L3m=2L3y_{cm} = \frac{2m \cdot L}{3m} = \frac{2L}{3}
  4. So the answer is (c) (L6,2L3)\left(\frac{L}{6}, \frac{2L}{3}\right).
Report a mistake

More questions on Composite & Cut-Out Bodies