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JEE Main 2016 (10 Apr, Shift 1) · Combination of Capacitors

Combination of Capacitors question from JEE Main 2016 (10 Apr, Shift 1)

Q84JEE Main 2016 · 10 APR · SHIFT 1Medium

Combination of Capacitors

Figure shows a network of capacitors where the numbers indicates capacitances in micro Farad. The value of capacitance C if the equivalent capacitance between point A and B is to be 1 μ\muF is:

Figure

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Answer: (b)

  1. Left branch: 2∥2=42 \parallel 2 = 4, in series with 88: 83\frac{8}{3}.
  2. Right branch: 66 and 1212 in series =4= 4, in parallel with 44: 88; in series with 11: 89\frac{8}{9}.
  3. Below C: 83+89=329\frac{8}{3} + \frac{8}{9} = \frac{32}{9}.
  4. 1C+932=1⇒C=3223 μF\frac{1}{C} + \frac{9}{32} = 1 \Rightarrow C = \frac{32}{23}\ \mu\text{F}
  5. So the answer is (b) 3223 μF\frac{32}{23}\ \mu\text{F}.
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