Moment of Inertia & Radius of Gyration question from MHT CET 2021 (23 Sep, Shift 1)

Answer: (c)

1. $I$ is largest about the axis from which the mass lies farthest on average.
2. $QS$ and $QT$ pass through the lamina, so mass lies close on both sides; $PR$ (hypotenuse) has the shortest perpendicular height.
3. About a leg, $I = \frac{Mh^2}{6}$ with $h$ the other leg. For $QR$, $h = PQ$, the longer leg; for $PQ$, $h = QR$, the shorter one.
4. So $I$ is maximum about (c) QR.