Find the capacitance of the Parallel plate capacitor shown in the figure. (A = area of each plate, ε₀ = permittivity of free space) (a) (2KAε₀)/((K+1)d) (b) (2KAε₀)/(d) (c) ((K+1)Aε₀)/(2d) (d) (2KAε₀)/((K²+1)d)

Answer: (a). Slab of thickness d/2 and air gap d/2 act in series. C=(ε₀A)/(d/2+d/2K)=(2KAε₀)/((K+1)d) So the answer is (a).

Find the capacitance of the Parallel plate capacitor shown in the… | MHT CET 2026 (13 May, Shift 1)

Q19MHT CET 2026 · 13 MAY · SHIFT 1Medium

Dielectrics

Find the capacitance of the Parallel plate capacitor shown in the figure.

(A = area of each plate, $\varepsilon_0$ = permittivity of free space)

Show answer and solution

Answer: (a)

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