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MHT CET 2024 (3 May, Shift 1) · P-N Junction Diode

P-N Junction Diode question from MHT CET 2024 (3 May, Shift 1)

Q47MHT CET 2024 · 3 MAY · SHIFT 1Medium

P-N Junction Diode

Find the magnitude of current in the given circuit.

Figure

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Answer: (a)

  1. The 44 V cell (positive towards A) tries to drive current from right to left, and the 11 V cell (positive towards B) from left to right.
  2. Net emf =4−1=3= 4 - 1 = 3 V, which drives current from right to left.
  3. The diode points from left to right, so for this current it is reverse biased.
  4. An ideal reverse biased diode allows no current, so I=0I = 0.
  5. So the answer is (a) zero ampere.
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