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MHT CET 2019 (2 May, Shift 2) · Stationary Waves & Vibrating Strings

Stationary Waves & Vibrating Strings question from MHT CET 2019 (2 May, Shift 2)

Q89MHT CET 2019 · 2 MAY · SHIFT 2Easy

Stationary Waves & Vibrating Strings

Find the wrong statement from the following about the equation of stationary wave given by Y=0.04cos⁡(πx)sin⁡(50πt) mY = 0.04\cos(\pi x)\sin(50\pi t)\text{ m} where tt is in second. Then for the stationary wave.

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Answer: (a)

  1. ω=50π⇒T=2π50π=0.04 s\omega = 50\pi \Rightarrow T = \frac{2\pi}{50\pi} = 0.04\text{ s}, so (a) is wrong.
  2. k=π⇒λ=2 mk = \pi \Rightarrow \lambda = 2\text{ m}; v=ωk=50 m/sv = \frac{\omega}{k} = 50\text{ m/s}: (b), (c) true.
  3. Each component wave has amplitude 0.042=0.02 m\frac{0.04}{2} = 0.02\text{ m}: (d) true.
  4. So the wrong statement is (a).
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