Five equal resistances each of resistances R are connected as shown… | NEET 2004 (AIPMT)

Q78NEET 2004 · AIPMTMedium

Combination of Resistors

Five equal resistances each of resistances R are connected as shown in the figure. A battery of V volts is connected between A and B. The current flowing in AFCEB will be

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Answer: (c)

A is joined to F and B to E. Between F and E there are two paths, F–C–E and F–D–E, each $2R$ , with CD as a bridge.
By symmetry C and D are at the same potential (balanced bridge), so CD carries no current.
Each path gets voltage $V$ , so current in FCE $= \dfrac{V}{2R}$ .
So the answer is (c) $\dfrac{V}{2R}$ .

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