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JEE Main 2021 (27 Aug, Shift 1) · Cells: EMF, Internal Resistance & Combinations

Cells: EMF, Internal Resistance & Combinations question from JEE Main 2021 (27 Aug, Shift 1)

Q27JEE Main 2021 · 27 AUG · SHIFT 1Medium

Cells: EMF, Internal Resistance & Combinations

Five identical cells each of internal resistance 1Ω\Omega and emf 5V are connected in series and in parallel with an external resistance 'R'. For what value of 'R', current in series and parallel combination will remain the same?

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Answer: (a)

  1. Series: Is=5ER+5r=25R+5I_s = \dfrac{5E}{R + 5r} = \dfrac{25}{R + 5}.
  2. Parallel: Ip=ER+r/5=5R+0.2I_p = \dfrac{E}{R + r/5} = \dfrac{5}{R + 0.2}.
  3. Is=Ip⇒25(R+0.2)=5(R+5)⇒20R=20I_s = I_p \Rightarrow 25(R + 0.2) = 5(R + 5) \Rightarrow 20R = 20
  4. So the answer is (a) R=1 ΩR = 1\ \Omega.
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