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MHT CET 2026 (11 Apr, Shift 1) · Electric Potential & Equipotentials

Electric Potential & Equipotentials question from MHT CET 2026 (11 Apr, Shift 1)

Q19MHT CET 2026 · 11 APR · SHIFT 1Medium

Electric Potential & Equipotentials

Following figure indicates the electric potential V as a function through 4 regions on x-axis. Which of the following is correct for the electric field E in these regions?

Figure

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Answer: (c)

  1. E=−dVdxE = -\frac{dV}{dx}: magnitude of EE equals the slope of the VV–xx graph.
  2. Regions 1 (AB) and 3 (CD) are flat: E1=E3=0E_1 = E_3 = 0.
  3. Region 4 (DE) is much steeper than region 2 (BC), so E2<E4E_2 < E_4.
  4. So the answer is (c) E1=E3E_1 = E_3 and E2<E4E_2 < E_4.
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