For a body of mass ' m ', the acceleration due to gravity at a distance ' R ' from the surface of the earth is (g/4). Its value at a distance (R/2) from the surface of the earth is ( R = radius of the earth, g = acceleration due to gravity) (a) (g/8) (b) (9g/4) (c) (4g/9) (d) (g/2)

Answer: (c). At height h: gh = g(R²)/((R+h)²); at h = R this gives g/4, as stated. At h = R/2: gh = g(R²)/((3R/2)²) = 4g/9 So the answer is (c) 4g/9.

For a body of mass ' m ', the acceleration due to gravity at a… | MHT CET 2021 (21 Sep, Shift 2)

Q94MHT CET 2021 · 21 SEP · SHIFT 2Medium

Acceleration Due to Gravity

For a body of mass ' $m$ ', the acceleration due to gravity at a distance ' $R$ ' from the surface of the earth is $\left(\frac{g}{4}\right)$ . Its value at a distance $\left(\frac{R}{2}\right)$ from the surface of the earth is ( $R =$ radius of the earth, $g =$ acceleration due to gravity)

Show answer and solution

Answer: (c)

At height $h$ : $g_h = g\frac{R^2}{(R+h)^2}$ ; at $h = R$ this gives $\frac{g}{4}$ , as stated.
At $h = \frac{R}{2}$ : $g_h = g\frac{R^2}{\left(\frac{3R}{2}\right)^2} = \frac{4g}{9}$
So the answer is (c) $\frac{4g}{9}$ .

Report a mistake

Acceleration Due to Gravity question from MHT CET 2021 (21 Sep, Shift 2)

More questions on Acceleration Due to Gravity