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MHT CET 2024 (2 May, Shift 2) · Energy in SHM

Energy in SHM question from MHT CET 2024 (2 May, Shift 2)

Q32MHT CET 2024 · 2 MAY · SHIFT 2Medium

Energy in SHM

For a body performing simple harmonic motion, its potential energy is $E_x$ at displacement x and $E_y$ at displacement y from mean position. The potential energy $E_0$ at displacement $(x+y)$ is

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Answer: (d)

$E = \frac{1}{2}kx^2 \Rightarrow$ displacement $\propto \sqrt{E}$ .
$\sqrt{E_0} = \sqrt{E_x} + \sqrt{E_y}$
$E_0 = E_x + E_y + 2\sqrt{E_xE_y}$
So the answer is (d).

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