For a common-emitter amplifier, the voltage gain is 40. Its input and output impedances are 100 Ω and 400 Ω, respectively. The power gain of the CE amplifier will be (a) 450 (b) 400 (c) 300 (d) 500

Answer: (b). AV = β(Ro)/(Ri) ⇒ β = (40 × 100)/(400) = 10 AP = β AV = 10 × 40 = 400 So the answer is (b) 400.

For a common-emitter amplifier, the voltage gain is 40. Its input and… | MHT CET 2021 (22 Sep, Shift 2)

Q66MHT CET 2021 · 22 SEP · SHIFT 2Easy

Junction Transistor

For a common-emitter amplifier, the voltage gain is 40. Its input and output impedances are $100\ \Omega$ and $400\ \Omega$ , respectively. The power gain of the CE amplifier will be

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Answer: (b)

$A_V = \beta\frac{R_o}{R_i} \Rightarrow \beta = \frac{40 \times 100}{400} = 10$
$A_P = \beta A_V = 10 \times 40 = 400$
So the answer is (b) 400.

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