Physics Circle home Student Login

Home›Chapters›Ray Optics PYQs›Spherical Surfaces & Thin Lenses›Question 87

JEE Main 2020 (5 Sep, Shift 1) · Spherical Surfaces & Thin Lenses

Spherical Surfaces & Thin Lenses question from JEE Main 2020 (5 Sep, Shift 1)

Q87JEE Main 2020 · 5 SEP · SHIFT 1Medium

Spherical Surfaces & Thin Lenses

For a concave lens of focal length f, the relation between object and image distances u and v, respectively, from its pole can best be represented by (u = v is the reference line):

Show answer and solution

Answer: (d)

  1. Concave lens: ∣v∣=∣u∣f∣u∣+f|v| = \frac{|u| f}{|u| + f}, always less than ∣u∣|u| and less than ff.
  2. For small ∣u∣|u|, ∣v∣≈∣u∣|v| \approx |u|, so the curve starts along the line u=vu = v.
  3. As ∣u∣→∞|u| \to \infty, ∣v∣→f|v| \to f, approaching the dotted line from below without crossing u=vu = v.
  4. So the answer is (d).
Report a mistake

More questions on Spherical Surfaces & Thin Lenses