For a constant collector-emitter voltage of 8 V, the collector current of a transistor reached to the value of 6 mA from 4 mA, whereas base current changed from 20 to 25 value. If transistor is in active state, small signal current gain (current amplification factor) will be: (a) 240 (b) 400 (c) 0.0025 (d) 200

Answer: (b). β = (Δ IC)/(Δ IB) at constant VCE Δ IC = 2 mA = 2000 μ A, Δ IB = 5 μ A β = 2000/5 = 400 So the answer is (b) 400.

For a constant collector-emitter voltage of 8 V, the collector… | JEE Main 2022 (27 Jul, Shift 2)

Q51JEE Main 2022 · 27 JUL · SHIFT 2Easy

Junction Transistor

For a constant collector-emitter voltage of $8\text{ V}$ , the collector current of a transistor reached to the value of $6\text{ mA}$ from $4\text{ mA}$ , whereas base current changed from $20\,\mu\text{A}$ to $25\,\mu\text{A}$ value. If transistor is in active state, small signal current gain (current amplification factor) will be:

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Answer: (b)

$\beta = \frac{\Delta I_C}{\Delta I_B}$ at constant $V_{CE}$
$\Delta I_C = 2$ mA $= 2000\,\mu$ A, $\Delta I_B = 5\,\mu$ A
$\beta = 2000/5 = 400$
So the answer is (b) 400.

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