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JEE Main 2021 (25 Jul, Shift 1) · Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation question from JEE Main 2021 (25 Jul, Shift 1)

Q41JEE Main 2021 · 25 JUL · SHIFT 1Medium

Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

For a gas CP −- CV = R in a state P and CP −- CV = 1.10 R in a state Q, TP and TQ are the temperatures in two different states P and Q respectively. Then

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Answer: (d)

  1. CP−CV=RC_P - C_V = R holds exactly only for an ideal gas.
  2. A real gas behaves most ideally at high temperature (and low pressure).
  3. In state P the gas follows CP−CV=RC_P - C_V = R (ideal), in Q it deviates (1.10 R), so Q is at lower temperature.
  4. So the answer is (d) TP>TQT_P > T_Q.
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