For a gas having ' X ' degrees of freedom, ' γ ' is ( γ = ratio of specific heats = CP/CV) (a) 1+X/2 (b) 1 + X/2 (c) 1 + 2/x (d) 1 + 1/x

Answer: (c). Cv = X/2R, Cp = (X/2+1)R. γ = 1 + 2/X So the answer is (c) 1 + 2/X.

For a gas having ' X ' degrees of freedom, ' γ ' is ( γ = ratio of… | MHT CET 2023 (9 May, Shift 1)

Q27MHT CET 2023 · 9 MAY · SHIFT 1Easy

Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

For a gas having ' $X$ ' degrees of freedom, ' $\gamma$ ' is ( $\gamma =$ ratio of specific heats $= C_P/C_V$ )

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Answer: (c)

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