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MHT CET 2020 (16 Oct, Shift 1) · Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation question from MHT CET 2020 (16 Oct, Shift 1)

Q44MHT CET 2020 · 16 OCT · SHIFT 1Easy

Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

For a gas, RCV=0.4\frac{R}{C_V} = 0.4, where RR is universal gas constant and CVC_V is the molar specific heat at constant volume. The gas is made up of molecules, which are

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Answer: (b)

  1. Cv=R0.4=52R⇒f=5C_v = \frac{R}{0.4} = \frac{5}{2}R \Rightarrow f = 5.
  2. So the answer is (b) rigid diatomic.
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