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MHT CET 2026 (11 Apr, Shift 2) · Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation question from MHT CET 2026 (11 Apr, Shift 2)

Q5MHT CET 2026 · 11 APR · SHIFT 2Easy

Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

For a gas, RCv=0.4\frac{R}{C_v} = 0.4 where R is the universal gas constant and CvC_v is the molar specific heat at constant volume. The gas is made up of molecules which are

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Answer: (d)

  1. Cv=R0.4=52RC_v = \frac{R}{0.4} = \frac{5}{2}R
  2. f2=52⇒f=5\frac{f}{2} = \frac{5}{2} \Rightarrow f = 5
  3. So the answer is (d) rigid diatomic.
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