For a given transistor amplifier circuit in CE configuration VCC = 1 V, RC = 1 kΩ, Rb = 100 kΩ and β = 100. Value of base current Ib is (a) Ib = 100 (b) Ib = 0.1 (c) Ib = 1.0 (d) Ib = 10

Answer: (d). Maximum (saturation) collector current: IC = VCCRC = (1 V)/(1 kΩ) = 1 mA Base current: Ib = (IC)/(β) = (1 mA)/(100) = 10 So the answer is (d) Ib = 10.

For a given transistor amplifier circuit in CE configuration VCC = 1… | JEE Main 2023 (8 Apr, Shift 2)

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Junction Transistor

For a given transistor amplifier circuit in $\text{CE}$ configuration $\mathrm{V}_{\mathrm{CC}} = 1\text{ V}, \mathrm{R}_{\mathrm{C}} = 1\text{ k}\Omega, \mathrm{R}_{\mathrm{b}} = 100\text{ k}\Omega$ and $\beta = 100$ . Value of base current $\mathrm{I}_{\mathrm{b}}$ is

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Answer: (d)

Maximum (saturation) collector current: $I_C = \dfrac{V_{CC}}{R_C} = \dfrac{1\ \text{V}}{1\ \text{k}\Omega} = 1\ \text{mA}$
Base current: $I_b = \dfrac{I_C}{\beta} = \dfrac{1\ \text{mA}}{100} = 10\ \mu\text{A}$
So the answer is (d) $I_b = 10\ \mu\text{A}$ .

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