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MHT CET 2026 (17 Apr, Shift 1) · Energy in SHM

Energy in SHM question from MHT CET 2026 (17 Apr, Shift 1)

Q5MHT CET 2026 · 17 APR · SHIFT 1Easy

Energy in SHM

For a particle executing S.H.M., its potential energy is 8 times its kinetic energy at a certain displacement ' $x$ ' from the mean position. If ' $A$ ' is the amplitude of S.H.M., the value of ' $x$ ' is

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Answer: (c)

$PE = 8\,KE \Rightarrow x^2 = 8(A^2 - x^2)$
$9x^2 = 8A^2 \Rightarrow x = \dfrac{2\sqrt{2}}{3}A$
So the answer is (c).

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