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JEE Main 2010 (AIEEE) · Centripetal Acceleration & Force

Centripetal Acceleration & Force question from JEE Main 2010 (AIEEE)

Q51JEE Main 2010 · AIEEEMedium

Centripetal Acceleration & Force

For a particle in uniform circular motion the accelerationa⃗\vec{a}at a point P(R, θ) on the circle of radius R is (here θ is measured from the x–axis)

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Answer: (c)

  1. Acceleration in UCM is v2R\frac{v^2}{R} directed from P to the centre O.
  2. Unit vector from O to P is cos⁡θ i^+sin⁡θ j^\cos\theta\,\hat{i} + \sin\theta\,\hat{j}, so a⃗\vec a is along its negative.
  3. a⃗=−v2Rcos⁡θ i^−v2Rsin⁡θ j^\vec a = -\frac{v^2}{R}\cos\theta\,\hat{i} - \frac{v^2}{R}\sin\theta\,\hat{j}
  4. So the answer is (c).
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